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Desafio geométrico que parece simples, mas exige atenção aos detalhes. O ângulo externo indicado mede 110°. Como ele forma um par linear com o ângulo interno da base do triângulo, calculamos o seu suplementar. Ângulos suplementares somam 180°, portanto 180° − 110° = 70°. Esse ângulo de 70° é um dos ângulos internos do triângulo. Observando as marcações, percebemos que o triângulo é isósceles, pois possui dois lados congruentes. Em um triângulo isósceles, os ângulos da base são congruentes. Log
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Para encontrar o ângulo pedido, começamos observando que o ângulo de 70° indicado fora do triângulo é oposto pelo vértice ao ângulo interno formado pelo cruzamento das duas retas. Ângulos opostos pelo vértice possuem a mesma medida, portanto esse ângulo interno também mede 70°. Agora analisamos o triângulo maior à esquerda. Já conhecemos dois ângulos dele: 70° e 40°. A soma dos ângulos internos de qualquer triângulo é 180°. Logo, o terceiro ângulo desse triângulo é: 180° − = 70° A
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À primeira vista esse problema parece complicado, mas a solução sai apenas com relações básicas de ângulos. O primeiro passo é observar o ângulo de 110° na linha horizontal superior. O ângulo interno do triângulo ao lado dele é suplementar, pois ambos formam uma linha reta. Ângulos suplementares somam 180°. Portanto: 180° − 110° = 70° Esse é o primeiro ângulo interno do triângulo. O desenho indica que o triângulo é isósceles, pois dois lados possuem a mesma marca. Em um triângulo isósceles,
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